Difference between revisions of "The old website"

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=== What was it about? ===
 
=== What was it about? ===
  
The majority of the pages was about how to connect to the grid made for SHA2017 safely and how to build a grid yourself. Some test results on cheap Chinese DC-DC converters, some tips on how to generate electricity or heat and some user projects were explained on other pages.
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The majority of the pages was about how to connect to the grid made for SHA2017 safely and how to build a grid yourself. Some test results on cheap Chinese DC-DC converters, some tips on how to generate electricity or heat and some user projects were explained on other pages. Let's try to sum it all up below.
  
  
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We wanted to be somewhere in the middle, safe but without to much losses. Our grid voltage was specced on 42V +/- 15%. Why 42? [https://en.wikipedia.org/wiki/Phrases_from_The_Hitchhiker%27s_Guide_to_the_Galaxy#Answer_to_the_Ultimate_Question_of_Life,_the_Universe,_and_Everything_(42) It's the answer to the Ultimate Question of Life, the Universe, and Everything!] That and voltages below 60VDC ([https://www.cui.com/catalog/resource/iec-62368-1-an-introduction-to-the-new-safety-standard-for-ict-and-av-equipment.pdf IEC 62368-1:ES1]) are believed safe to touch in most conditions. At 42V+15% were at about 48V, leaving some room for safety systems to kick in and leaves a little bit for AC ripple too.
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We wanted to be somewhere in the middle, safe but without to much losses. Our grid voltage was specced on 42V +/- 15%. Why 42? [https://en.wikipedia.org/wiki/Phrases_from_The_Hitchhiker%27s_Guide_to_the_Galaxy#Answer_to_the_Ultimate_Question_of_Life,_the_Universe,_and_Everything_(42) It's the answer to the Ultimate Question of Life, the Universe, and Everything!] That and voltages below 60VDC ([https://www.cui.com/catalog/resource/iec-62368-1-an-introduction-to-the-new-safety-standard-for-ict-and-av-equipment.pdf IEC 62368-1:ES1]) are believed safe to touch in most conditions. At 42V+15% were at about 48V, leaving some room for safety systems to kick in and leaves a little bit for AC ripple too. Looking back at SHA2017, 48V could have been used too, with maybe a bit tighter +/-10% voltage range. This had maybe helped a bit in finding suitable gear to hook up to the grid. You can keep that in mind if you want to build your own grid.
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So, now what, we want to build a grid, what's needed? Basically just some cables, fuses, and maybe a system that dissipates some power if the voltage rises too much. Cables can be thin for short distances or low currents and must be thicker when greater distances have to be crossed, high currents are possible or when voltage drop needs to be low. Loads that need a large startup current, like big motors, also need bigger cables or a buffer of some kind nearby the load.
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An example:
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* A piece of wire with 2 2.5mm2 copper conductors of 10m long has a resistance of about 0.17 Ohms. The voltage on one end is 42V, on the other end a 120Vac 2000W tea kettle is connected. The kettle has a resistance of about 7.2 Ohms. In total the resistance is 7.37 Ohms resulting in a current draw of 5.7 Amps. The voltage drop percentage as well as the cable power loss percentage is calculated by dividing the total resistance with the cable resistance, about 2.3%. Total power used is about 240W with 5.5W of it being transformed into heat inside the cable. To warm up a liter of water from 10 to 100 degrees Celsius you need about 100Wh. So you can have half a liter of tea in about 15 minutes if the insulation on the kettle is not too bad. But if you have had a 50m 1.0mm2 aluminium cable, can you still have tea? Well, yes, but it would take much longer as your cable has a resistance of 3,2 Ohms, resulting in only about 4A of current and 170W of total power use of which about 50W is lost inside the cable. Still you could have that tea in about half an hour or so.
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* If you have a load that needs a 50A startup current and has a running current of about 4A (let's say a 160W fridge driven by a 42-230V 2000W DC-AC sine-wave inverter) you must choose your cable with much more care. You probably don't want the voltage to drop more than 10%. That means the cable resistance has to be 9 times smaller than the equivalent startup resistance seen at the input of the inverter. The input resistance at 42V-10% equals (42-4.2)/50A = 0,76 Ohms. That means that now your 10m 2.5mm cable is not close to what you need, it could even result in fire. You'll need at least a 6mm2 cable of 10m for this! To cross 50m you'll need an enormous 35mm2 cable. Or you can place a battery pack nearby the fridge that can handle the peak current easily, that way you can use a cable that is much smaller, a 2.5mm copper cable of 50m is now suitable for the task. For those kinds of loads, '''decentralization''' is the key. Put your battery packs nearby the most demanding loads, it keeps the grid more stable and it saves on cable costs and on cable losses!

Revision as of 14:34, 28 July 2019

What was it about?

The majority of the pages was about how to connect to the grid made for SHA2017 safely and how to build a grid yourself. Some test results on cheap Chinese DC-DC converters, some tips on how to generate electricity or heat and some user projects were explained on other pages. Let's try to sum it all up below.


Safety third, err, first!

While high voltage grids are more efficient in transporting power over long distances, it makes the system way more complex and many safety measures must be implemented to avoid shocks and risk of fire. Not the way to go on a damp camping field and inside tents. A very low voltage on the other hand is much safer, but cable losses are much greater or, to minimize those losses, cables need to be very thick and expensive. This is because, at the same power, current rises when voltage drops. A 60W laptop charges needs about 0.2A at 300V. At 12V this would be 5A, 25 times as much. Simply said, a cable can be seen as a resistor, cable loss can be calculated at P=I^2*R, for the same cable a current increase of 25 times would mean a power loss factor of 625 times more! You should therefore use much thicker cables at low voltages.


We wanted to be somewhere in the middle, safe but without to much losses. Our grid voltage was specced on 42V +/- 15%. Why 42? It's the answer to the Ultimate Question of Life, the Universe, and Everything! That and voltages below 60VDC (IEC 62368-1:ES1) are believed safe to touch in most conditions. At 42V+15% were at about 48V, leaving some room for safety systems to kick in and leaves a little bit for AC ripple too. Looking back at SHA2017, 48V could have been used too, with maybe a bit tighter +/-10% voltage range. This had maybe helped a bit in finding suitable gear to hook up to the grid. You can keep that in mind if you want to build your own grid.


So, now what, we want to build a grid, what's needed? Basically just some cables, fuses, and maybe a system that dissipates some power if the voltage rises too much. Cables can be thin for short distances or low currents and must be thicker when greater distances have to be crossed, high currents are possible or when voltage drop needs to be low. Loads that need a large startup current, like big motors, also need bigger cables or a buffer of some kind nearby the load.

An example:

  • A piece of wire with 2 2.5mm2 copper conductors of 10m long has a resistance of about 0.17 Ohms. The voltage on one end is 42V, on the other end a 120Vac 2000W tea kettle is connected. The kettle has a resistance of about 7.2 Ohms. In total the resistance is 7.37 Ohms resulting in a current draw of 5.7 Amps. The voltage drop percentage as well as the cable power loss percentage is calculated by dividing the total resistance with the cable resistance, about 2.3%. Total power used is about 240W with 5.5W of it being transformed into heat inside the cable. To warm up a liter of water from 10 to 100 degrees Celsius you need about 100Wh. So you can have half a liter of tea in about 15 minutes if the insulation on the kettle is not too bad. But if you have had a 50m 1.0mm2 aluminium cable, can you still have tea? Well, yes, but it would take much longer as your cable has a resistance of 3,2 Ohms, resulting in only about 4A of current and 170W of total power use of which about 50W is lost inside the cable. Still you could have that tea in about half an hour or so.
  • If you have a load that needs a 50A startup current and has a running current of about 4A (let's say a 160W fridge driven by a 42-230V 2000W DC-AC sine-wave inverter) you must choose your cable with much more care. You probably don't want the voltage to drop more than 10%. That means the cable resistance has to be 9 times smaller than the equivalent startup resistance seen at the input of the inverter. The input resistance at 42V-10% equals (42-4.2)/50A = 0,76 Ohms. That means that now your 10m 2.5mm cable is not close to what you need, it could even result in fire. You'll need at least a 6mm2 cable of 10m for this! To cross 50m you'll need an enormous 35mm2 cable. Or you can place a battery pack nearby the fridge that can handle the peak current easily, that way you can use a cable that is much smaller, a 2.5mm copper cable of 50m is now suitable for the task. For those kinds of loads, decentralization is the key. Put your battery packs nearby the most demanding loads, it keeps the grid more stable and it saves on cable costs and on cable losses!